X=-y^2+3y-4

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Solution for X=-y^2+3y-4 equation: 



X=-X^2+3X-4

We move all terms to the left:

X-(-X^2+3X-4)=0

We get rid of parentheses

X^2-3X+X+4=0

We add all the numbers together, and all the variables

X^2-2X+4=0

a = 1; b = -2; c = +4;
Δ = b2-4ac
Δ = -22-4·1·4
Δ = -12
Delta is less than zero, so there is no solution for the equation

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